![]() Am I just burning my brain up over this? Can anyone post their thoughts? Any help would be appreciated. That's not going to produce a deflection similiar to the deflection I would have with a 350 ohm meter movement. It seems to me that the current flow would be divided approximately 25% thru the 1500 ohm meter and 75% through the 470 ohm resistor. But, will this give me the same needle deflection as the original would have? As I'm asking this I'm starting to think that it won't. ![]() I'm thinking that by doing so I will now have the (approximate) total resistance that the original meter presented to the circuit. My question is this: I know that if I put a 470 ohm resistor in parallel with the meter the total resistance will equal approximately 360 ohms. ![]() However, the new meter ohms shows a resistance of 1500 ohms. It took a little "customizing" but it matches very, very close to the position of the former "0-50 Ma" face plate. ![]() I've also very carefully opened the new meter and swapped the old meter face ("Bad-Weak-Good") into it. I've gotten a replacement 50 Ma meter which will physically fit the opening on the front panel, so mounting is not a problem. The schematic identifies it as "50 Ma - 350 ohm". I have a preevious post about my EMC tube tester meter being open and unrepairable. I'm wondering if someone has advice or help with my problem.
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